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Mathematics 20 Online
OpenStudy (anonymous):

Sum function..

OpenStudy (anonymous):

Can someone help me find the sum function to: \[\sum_{n=0}^{∞}(a*n+b)x^n\] :)

OpenStudy (experimentx):

depends on what your value of x is, if |x| < 1, then separate the bracket, first term will be arithmetic-geometric series and second will be geometric series

OpenStudy (experimentx):

if |x|>=1, then it diverges

OpenStudy (anonymous):

I have been given a hint: \[\sum_{n=0}^{∞}x^n=1/(1-x)\] And \[\sum_{n=0}^{∞}\frac{ 1 }{ (1-x)^2 }\]

OpenStudy (amistre64):

\[\sum( an+b)x^n\] \[\sum an~x^n+bx^n\] \[\sum an~x^n+\sum bx^n\] \[a\sum n~x^n+b\sum x^n\] not real sure where thats going tho

OpenStudy (experimentx):

your given hint applies if and only if |x|<1

OpenStudy (anonymous):

I must find the answer for all pairs of constants a and b (not both zero). It shall also indicate for which x formula is valid.

OpenStudy (experimentx):

the condition is i stated it above. \[ \sum_{n=0}^\infty nx^n = \sum_{n=0}^\infty x \frac{d(x^n)}{dx} = x \frac{d(\sum x^n)}{dx} = x \; \frac{d}{dx}(1/(1-x))\] you can interchange the order of differentiation because for |x|<1, the series converges uniformly. also there is a quick trick without differentiation.

OpenStudy (anonymous):

Thank you @experimentX and @amistre64

OpenStudy (experimentx):

yw

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