Question

(12x^2yz)^2 ??
how should i solve this?

Answer 1

well its really

\[12^2 \times (x^2)^2 \times y^2 \times z^2\]

simplify the power of x and find 12^2

for the answer

Answer 2

the power of 2 operates on each part of the term

Answer 3

So would it be 144x^4 y^2 z^2?

Answer 4

thats correct

Answer 5

what if it was (u^3 over 6) ^2?

Answer 6

well then its

\[\frac{(u^3)^2}{6^2}\]

Answer 7

you just need to simplify it

Answer 8

what would u's power be, 6 or 5?

Answer 9

the law for power of a power is

\[(x^a)^b = x^{a \times b}\]

this is the law you need to simplify the power