Question

The sum of the reciprocals of two consecutive even integers is 9/40 Write an equation that can be used to find the two integers. What are the integers?

Answer 1

@Mertsj

Answer 2

Let x = first integer
x+2 = next consecutive even integer
1/x=reciprocal of first integer
1(/x+2)= reciprocal of next consecutive even integer
Write the equation that says the sum of the reciprocals = 9/40

Answer 3

So 1(/x+2)=9/40?

Answer 4

What is the reciprocal of the first integer?

Answer 5

1/x

Answer 6

What is the reciprocal of the next consecutive even integer?

Answer 7

x+2

Answer 8

Reread my first post. What is the RECIPROCAL of the next consecutive even integer?

Answer 9

1(/x+2)

Answer 10

How do you find a sum?

Answer 11

By multiplying?

Answer 12

A sum is the answer to an addition problem.

Answer 13

What is the sum of the two RECIPROCALS?

Answer 14

How could you add?

Answer 15

The sum of 2 and 3 is 2+3
The sum of x and y is x+y
The sum of 1/x and 1/(x+2) is ?????

Answer 16

OH!

1/x +1/(x+2)

2/2x+3?

Answer 17

\[\frac{1}{x}+\frac{1}{x+2}=\frac{9}{40}\]

Answer 18

Sorry, im just so confused.

Answer 19

Solve that equation.
Multiply both sides by the common denominator which is 40x(x+2)

Answer 20

80 x (x+2)+40 (x+2)+1/x = 9 x (x+2)?

Answer 21

Is that right?

Answer 22

x=-10/9,8?

Answer 23

..

Answer 24

Mertsj, are you there?

Answer 25

Sorry. I was called away.