Question

Simple algebra 1

Answer 1

\[2^{\frac{ 5 }{ 2 }}-2^{\frac{ 3 }{ 2}}\]

Answer 2

What are those exponents? 5/2 and 3/2?

Answer 3

yes

Answer 4

Is it just 2^2/2 which is 2^1 which is 2?

Answer 5

@mrbarry

Answer 6

Nevermind, that can't be right...

Answer 7

If you were dividing the terms you would subtract exponents. You need to evaluate each term first then subtract. Remember in a fractional exponent the numberator is a power and the denominator is a root.

Answer 8

Do you mind to work it out?

Answer 9

So \[\sqrt[2]{2}^{5?}\]

Answer 10

So is the answer 2^2?

Answer 11

\[\sqrt{2^{5}} - \sqrt{2^{3}}\]

Can you evaluate and simplify that?

Answer 12

Would it be \[\sqrt{2^{3}}\]

Answer 13

sqrt(32)- sqrt(8) = 4 sqrt(2) - 2 sqrt(2)= 2 sqrt(2)

Answer 14

\[2^{\frac{ 3 }{ 2 }}\] is the answer!!!!!!!!!!!!!!!!!!

Answer 15

@mrbarry

Answer 16

Thanks @phi

Answer 17

You are welcome.

Answer 18

you could also do this
\[ 2^{\frac{ 5 }{ 2 }}-2^{\frac{ 3 }{ 2}} \\ 2^{\frac{ 2 }{ 2 }}2^{\frac{ 3 }{ 2 }}-2^{\frac{ 3 }{ 2}}\\ 2^{\frac{ 3 }{ 2 }}\left( 2-1\right)=2^{\frac{ 3 }{ 2 }} \]

Answer 19

Clever.