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OpenStudy (aravindg):
you mean sum of 10 terms?
OpenStudy (anonymous):
If these answers choices relate then yes:
256.5
511
1,023
2047
OpenStudy (saifoo.khan):
$10
OpenStudy (saifoo.khan):
| was missing. @AravindG
OpenStudy (aravindg):
Well this is a geometric progression
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OpenStudy (aravindg):
Can you find the common ratio ?
OpenStudy (anonymous):
*2?
OpenStudy (aravindg):
yes :)
OpenStudy (aravindg):
Now \[S_n=\dfrac{a(r^n-1)}{(r-1)}\]
OpenStudy (aravindg):
This is the sum formula .Put r=2 a=1
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OpenStudy (aravindg):
n=10 .You will get sum
OpenStudy (anonymous):
using the geometric formula, find out the 10th term:\[a_n=a(2)^{n-1}\]\[a_{10}=1(2)^{10-1}\]\[a_10=2^9\]\[a_10=512\]now using the formula for the sum of a finite geometric series, find the sum:\[{a_1(1-r^n)}\over1-r\]\[{1(1-2^10)}\over1-2\]\[(1-1024)\over-1\]\[-1023\over-1\]\[S_10=1023\]
OpenStudy (aravindg):
@yummydum you didnt leave anything to do for the asker ? :/
OpenStudy (anonymous):
wow im bad at this..
OpenStudy (saifoo.khan):
@AravindG : We have so many bad users here.. :l
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OpenStudy (aravindg):
Thats sad :/
OpenStudy (anonymous):
han! aur aik ho tum, kaminay kaheen k! :P
OpenStudy (anonymous):
i leave..
OpenStudy (anonymous):
0_0...
OpenStudy (aravindg):
@xkylex Dont mind our conversation..Did you understand how to do it?
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