Question

@johnweldon1993 this one confuses me
A motorboat travels 198 mi in 3 hours going upstream and 416 mi in 4 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?

Answer 1

if we assume the speed of boat be x and that of the current be y mi/h respectively
moving downstream(that is with the current ) relative speed is (x+y)
hence 4(x+y)=416 ....(x+y)=104
moving upstream(that is against the current ) relative speed is (x-y)
and 3(x-y)=198 ....(x-y)=66

solving for x and y we get the answers

Answer 2

Thank you @matricked , my wifi really does not like OS....You're in good hands @Mpinkham

Answer 3

adding the equations we get 2x=170
hence x=85 mi/h
putting the value of x in any eq we have y=19

Answer 4

welcome dear....
even most of the times i also have hardware probs

Answer 5

so then its 85 and 19??

Answer 6

That would be correct

Check them :D

3(85 - 19) = 198
4(85 + 19) = 416

True?

Answer 7

for boat its 85 mi/h and for current its 19mi/h

Answer 8

it is lol