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How does 1/B-1/A = AB/A-B?
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@dan815 @DLS
\[\frac{ 1 }{ \frac{ 1 }{ b } -\frac{ 1 }{ a }}=\frac{ ab }{ a-b }\]
But why do you put them over 1?
that one you posted is incorrect\[\frac{ 1 }{ b }-\frac{ 1 }{ a}=\frac{ a-b }{ ab } \]
Thank you! Missed that!
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@Jonask , why did you put it all over1?
well to make it equivalent to your result otherwise it wont work if you just leave it like that its not true \[\huge \frac{ a }{ b }+\frac{ c }{ d }=\frac{ ad+bc }{ bd }\]
Will you please also show me the steps for 1/b-1/a = a-b/ab? I need to see how you got it?
Thanks so much.
Nvm, you just did. God bless.
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