Question

Logarithms help? Question is in the picture below..

Answer 1

write that radical down as an exponent. that'd be the first step.

Answer 2

Can you explain that more? I'm not following..

Answer 3

OK, do you understand how \(\rm \sqrt[3]{stuff} = stuff^{1/3}\) or \(\rm \sqrt[6]{stuff} = stuff^{1/6}\)?

Answer 4

Yeah.. okay.. so it would be log a xy^1/9 ?

Answer 5

The problem base and answer base are different?

Answer 6

Yeah, \((xy)^{1/9}\).

So you have \(\log_b (xy)^{1/9}\). Do you know another rule related to this?

Answer 7

I just noticed that. The bases are supposed to be the same. My teacher does things like that all the time..

Answer 8

Uhh... no. :/

Answer 9

\[\log_ z x^{y} = y \log_z x\]This one is very vital! You may need to memorize it.

Answer 10

So can you use the above rule?

Answer 11

oh.. i remember that one! so the answer would be b?

Answer 12

Yay!

Answer 13

Yay that's the right answer? lol

Answer 14

Yup.

Answer 15

so a=b ?

Answer 16

How did you get that though? If I may confirm.

Answer 17

Yes, in this problem a=b

Answer 18

@UnkleRhaukus Read above

Answer 19

Can you help me with one more? It's probably the same thing.. I did really bad in this section as you can tell..

Answer 20

OK. Let's start with observing what \(\frac{1}{3}\ln(e^{12})\) should be

Answer 21

Do you know how \(\ln(e^{k}) = k\), and how that happens?

Answer 22

no, i don't. well, i might, but i don't remember.

Answer 23

Do you know what \(\ln\) *is*?

Answer 24

natural log?

Answer 25

Yeah, so how would you interpret something like \(\ln(1)\)?

Answer 26

it equals 0.. thats about all i know

Answer 27

Before we proceed, you need to know what a log is.

Answer 28

\(\log_a b\) equals to a number that we must raise to \(a\) to get \(b\).

For example, \(\log_4 16\) equals \(2\) since you raise \(4\) to \(2\) to get \(16\). Do you get it?

Answer 29

okay. yes.

Answer 30

So for example, what would \(\log_ee^2\) be?

Answer 31

a^x = e^2

Answer 32

Eh?

Answer 33

Read what I wrote about logs again.

Answer 34

okay, what does your problem say? log e^2 I can't read what's between log and e