Question

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Solve for n:

Answer 1

@DoYourHomework

Answer 2

Hang on.

Answer 3

Ok

Answer 4

\[\frac{ 3n+2 }{ 7 } +\frac{ 2n-3 }{ 4 } = 1\]

break into smaller fractions.
\[\frac{ 3n }{ 7 }+\frac{ 2n }{ 4 }+\frac{ 2 }{ 7 }-\frac{ 3 }{ 4 } = 1\]

Try to get n by itself.

\[n(\frac{ 3 }{ 7 }+\frac{ 2 }{ 4 }) = 1 - \frac{ 2 }{ 7 } +\frac{ 3 }{ 4 }\]

Find a common denominator by multiplying 7 and 4
28 will be the common denominator

\[n(\frac{ 12 }{ 28 }+\frac{ 14 }{ 28 }) = \frac{ 28 }{ 28 }+\frac{ 21 }{ 28 }-\frac{ 8 }{ 28 }\]

Simplify

\[n(\frac{ 26 }{ 28 }) = \frac{ 41 }{ 28 }\]

\[n = \frac{ 41 }{ 28 } * \frac{ 28 }{ 26 }\]

The '28s' cancel so...

\[n = \frac{ 41 }{ 26 }\]

Answer 5

Do you understand?

Answer 6

Yes :)... that helps!