:) Use the quadratic formula to solve the problem. A soccer player throws the ball onto the field from the sideline. An equation modeling the ball's flight is h = -16t2 + 18t + 2. In how many seconds will the ball reach the ground? Choose one answer. a. in about 2 seconds b. in about 1.2 seconds c. in about 1.8 seconds d. Cannot be determined
So using your quadratic formula with -16 for 'a' 18 for 'b' and 2 for 'c' plug those into \[\frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\] you will get 2 times...1 of which will most likely be negative....but you can ignore that...since we only want the positive number
edit * you will get 2 results!*
|dw:1370046166372:dw| yes, the ball touches the ground when h(t)=0.
-4/32 or -1/8 ?
wait thats not even an option
not quite...try that again the 2 results I get are 1.22 and -.101
john, well done! xp
So how did i not get that. Wtf ugg oh well. Thanks
well no try it again though \[\frac{ -18\pm \sqrt{18^2 - 4(-16)(2)} }{ 2(-16) }\] is what you should have done
that is what i did.
there's a \(\pm\) in the formula. it is the "-" that is giving the answer 1.2
so then lets simplify whats under that radical 18² is 324 -4 times -16 times 2 is 128 so now you have \[\frac{ -18\pm \sqrt{452} }{ -32 }\]
*It's √452 because you add 324 and 128*
so now you evaluate the √452 ...which will give you 21.2602916254 so you have 2 equations \[\frac{ -18 + 21.2602916254 }{ -32 }\] and \[\frac{ -18 - 21.2602916254 }{ -32 }\]
so do those out and what are the 2 results you get?
Well...she left...regardless....There's the work :D lol
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