Have a couple of questions on a timed Math Quiz that I don't Understand, Please Help me to understand, Please be patient also. They will be in comment.
How many solutions does the following system have? y = -2/3 x + 3 and 2x + 3y = 9 one solution no solution infinitely many solutions cannot be determined
the second equation is written in the standard form. So let us change the first equation also into standard form. Can you do that?
@bookworm00981
I think. @rajee_sam
Ok lets write it then
We simplify it right. combine like terms?
there are no like terms. We have to write it like Ax + By = C. Bringing x and y together and getting rid of the fraction and make it look just like the second equation
Ok, let me try.
\[y = -\frac{ 2 }{ 3 }x +3\]
now rewrite it
I just went Blank... don't leave let me think for a second.
no I am here
I help 2 - 3 people at a time. So Even if I go in and out I will see to it that you get this
Haha I do that too.
are you doing this?
you need to focus on this. You can help others later
Trying..
I can do math, i just can't remember the steps.
Ok, am I supposed to multiply by three on both sides?
\[y = -\frac{ 2 }{ 3 }x + 3\]\[3y = 3 (-\frac{ 2 }{ 3 } x + 3)\]\[3y = -2x +9\]Bring the -2x to the other side. \[2x + 3y = 9\]
yes
Ok, let me give it a go.
now what do you see in both equations?
Ah drat, I cant draw on the equation like if it was a drawing...
I see three's on both sides...???
The first equation when I rewrote in standard form turned out to be 2x + 3y = 9 My second equation is 2x + 3y = 9 as well
Ok, so did we flip the equation?
you sound lost?
yes..... T_T
sorry lost connection for a sec.
Let me start over. Focus and ditch your friend for a few minutes. She will live. We have two equations given to us. Both are linear. First equation is in Slope-intercept form and the second one is in Standard form. For solving system of equations we need to have the equations in standard form.
Eqn. 1 \[y = -\frac{ 2 }{ 3 }x + 3\] Eqn. 2 \[2x + 3y = 9\]
I am not going to do anything to eqn. 2 for now. Now let us focus on Eqn 1
Eqn mean equation?
yes
So eqn. 1 I have to rewrite in standard form.
Ok, let me. 2/3x+y=3?
I have to get rid of the fractions too
so what do I do?
\[y = -\frac{ 2 }{ 3 }x + 3\]\[3y = 3 (-\frac{ 2 }{ 3 }x + 3 )\]\[3y = -2x + 9\]\[2x + 3y = 9\]
Umm...
Now your first eqn. has been rewritten as 2x + 3y = 9 Did you get that part?
Looking at your work trying too.
1st step was to get rid of the fraction in front of x
-2/3
multiply both sides of the equation by 3 ( The denominator)
3y = 3(-2/3 x + 3)
I thought I said that earlier? Oh well.
And I said yes to that And you wandered off after that So lets move on to the next. Did you understand upto now?
how I rewrote y = -2/3x + 3 as 2x + 3y = 9
Fairly well I suppose. I excell in all other subjects, yet I am like a child before confusing Algebra.
not to fret.
You are doing good
So now I have two equations. Eqn 1 2x + 3y = 9 Eqn . 2 2x + 3y = 9
What can you say about them both?
They are alike.
They are the same
So they will have infinitely many solutions
Oh. so they are are parallel.
They are infact the same line
Thanks.
yw
Another way to do this problem (probably the way they expect you to solve it) is put both equations in slope-intercept form: y = -2/3 x + 3 and 2x + 3y = 9 become \[ y= -\frac{2}{3}x +3 \\ y= -\frac{2}{3}x +3 \] they are the same line, and lay on top on one another, so you get an infinite number of solutions. If they had the same slope, and different y intercepts, they would be parallel and never intersect, hence no solution if they have different slopes, the lines will meet somewhere, and there is one solution (where they meet)
Join our real-time social learning platform and learn together with your friends!