What is the slope of the line 8x + 3y = 8 – 2x?
From the last problem we did, can you solve for y by subtracting 8x from both sides?
i have 3y=8-10x now what lol
now divide by 3 the Left hand side and LHS of the equation to solve for y
left hand side /right hand side*
okay well im wrong y= 2.6 - 3.3
\[\frac{3y}{3}=\frac{8-2x}{3}\]
wouldnt 8-2x/3 stay the same?
\[\frac{\cancel3y}{\cancel3}=\frac{8-2x}{3}\]\[\large y=\frac{8}{3}-\frac{\color{red}2x}{\color{red}3}\]
for 8/3 i have 2.6 repeating
that's your slope :) Your slope is the value that multiplies to your value of x it follows the form \[\large y=\color{red}mx +b\] and in this case your m=2/3
for 2/3 i have 0.66 repeating.
You don't need to put it in decimal form, necessarily
You could leave it as a fraction.
so y=2/3x + 2.6
and the 2.6 can stay as 8/3 too.
y=2/3x+8/3 so this is the answer all together?
you're only looking for your slope, right? i mentioned a few posts above where you can find your slope. your slope is multiplied by your "x"
yes
so your slope would be \[\huge y= \color{red}{\frac{2}{3}}x+\frac{8}{3}\] the RED portion,is yoru slope.it is multiplied by your x-value.
great! it will take a few more of these problems for me to fully get it hahah, thank you very much !
no problem, lol.
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