Question

how do you write 84^-3/4 in radical notation

Answer 1

84=2*2*3*7
so it becomes\[\sqrt[-3/4]{21} \sqrt{2} \]
so \[\sqrt{2}/\sqrt[4]{21^{3}}\]

Answer 2

thank you so much

Answer 3

\[84^{-3/4}\\
=(2^2\cdot3\cdot7)^{-3/4}\\=\frac1{(2^2\cdot3\cdot7)^{3/4}}\\
=\frac1{\sqrt[4]{(2^2\cdot3\cdot7)^{3}}}\\
=\frac1{\sqrt[4]{2^6\cdot3^3\cdot7^3}}\\
=\frac1{\sqrt[4]{2^4\cdot2^2\cdot3^3\cdot7^3}}\\
=\frac1{2\sqrt[4]{\cdot2^2\cdot3^3\cdot7^3}}\]