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Mathematics 14 Online
OpenStudy (anonymous):

U(x,y)=xy/(x+y), solve ∂U/∂x and ∂U/∂y

OpenStudy (anonymous):

The trick to computing partial derivatives is to consider every other variable a constant.

OpenStudy (anonymous):

yes, this I know, so tackle this as a standard quotient rule

OpenStudy (anonymous):

Indeed, for the first one (the partial derivative with respect to x) just think of y as if its some arbitrary constant \(c\) and then compute the derivative as you normally would.

OpenStudy (anonymous):

1/(x^2+2xy)

OpenStudy (anonymous):

No not quite.

OpenStudy (anonymous):

y^2/(x+y)^2

OpenStudy (anonymous):

Yes, that's correct.

OpenStudy (anonymous):

Now compute the partial derivative with respect to y.

OpenStudy (anonymous):

x^2/(x+y)2

OpenStudy (anonymous):

yep, looks like you're good to go.

OpenStudy (anonymous):

thanks!

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