Expand (2x + y)5.
Have you drawn yourself a triangle. It looks like you may need one.
This Is A Binomial Theorem
OH yes. You can use combinations to figure out the coefficients or just keep drawing the triangle. The triangle is quicker until you get to some higher powers.
Is There A Formula For This ?
\[(a+b)^n=\sum_{k=0}^n\begin{pmatrix}n\\k\end{pmatrix}a^{n-k}b^k\] \[\begin{align} (a+b)^1&=1(a+b)&&=a+b\\ (a+b)^2&=1a^2b^0+2a^1b^1+1a^0b^2&&=a^2+2ab+b^2\\ (a+b)^3&=1a^3b^0+3a^2b^1+3a^1b^2+a^0b^3&&=a^3+3a^2b+3ab^2+b^3\\ \vdots \end{align}\]
Are you good with the formula above?
I Think So.... I Just Plug Everything Inside ?
Yes. As long as you have the rows of the triangle on paper it's not a big deal. Just notice the pattern of how the exponents change and be careful when negatives are being raised to powers.
No Im Lost !
Let walk through it. There is a lot to do for a full expansion. Triangle row ----> 1 5 10 10 5 1 (Good?)
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