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Mathematics 10 Online
OpenStudy (anonymous):

Reviewing and in need of a refreshment.

OpenStudy (anonymous):

(4+2i)(3-5i)

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

use the FOIL rule here as well

jimthompson5910 (jim_thompson5910):

and keep in mind that i^2 = -1

OpenStudy (anonymous):

yeah, i know,. but i forget what i stands for .. i know how to simplify this question. Just a tangent off of this.

jimthompson5910 (jim_thompson5910):

i is the imaginary number \[\large i = \sqrt{-1}\]

jimthompson5910 (jim_thompson5910):

squaring both sides gives you \[\large i^2 = -1\]

OpenStudy (anonymous):

so would the answer be 2?

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

so 12- 10^2

jimthompson5910 (jim_thompson5910):

not sure how you got that

jimthompson5910 (jim_thompson5910):

oh you did 4*3 = 12 and 2i*(-5i) = -10i^2 right?

OpenStudy (anonymous):

yeah

jimthompson5910 (jim_thompson5910):

well -10i^2 = -10(-1) since i^2 = -1

OpenStudy (anonymous):

yeah.

jimthompson5910 (jim_thompson5910):

so -10i^2 = -10(-1) = 10 which means -10i^2 = 10

jimthompson5910 (jim_thompson5910):

but that's only part of the story

jimthompson5910 (jim_thompson5910):

you forgot about the other parts of the FOIL method

OpenStudy (anonymous):

i thought you multiply 4 and 3

jimthompson5910 (jim_thompson5910):

|dw:1370158240619:dw|

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