The areas of two similar triangles are 49 cm squared, and 16 cm squared. What is the ratio of the corresponding side lengths? Of the perimeters?
The best the to do to find the area is multiply, since the area is already found you should divide, after that add the sides up to ger your perimiter
A49 : 16 ; 49 : 4 B: 49 : 16; 16 : 49 C: 7 : 4 ; 7: 4 D: 7 : 4; 7 : 16
What's the sqrt of 49?
If the ratio of the area of two triangles is A:B, then the ratio of their side lengths and perimeters is √A:√B. So, Given that the ratio of the two triangles is 49:16, then the ratio of their side lengths and perimeters is √49:√16 = 7:4. Therefore, the answer is (c). Hope this helps...good luck!
can you answer that? I'll walk you through it
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