Question

Pleaseeeee help...
x/4 + 2x/3=11..

Answer 1

\[\large \frac{x}{4}+\frac{2x}{3}= 11\] first we need a common denominator,so we multiply both fractions by 4 and 3.

Answer 2

yeah i got 24 for the common denominator.

Answer 3

\[\large \frac{3}{3}*\frac{x}{4}+ \frac{4}{4}{*\frac{2x}{3}}=11\]\[\large \frac{3x}{12}+\frac{8x}{12} = 11\]now that our denominators are the same,wecan rewrite it as one fraction \[\large \frac{3x+8x}{12} = 11\]multiply by the reciprocal which is (1/12) or cross multiply to get rid of the fraction on the LHS of the equation \[\large 3x+8x= 132\] combine the stuff on the LHS of the equation \[\large 11x = 132\] divide both sides by 11 \[\large \frac{\cancel {11}x}{\cancel{11}}= \frac{132}{11}\] simplify and you'll have your answer :)

Answer 4

sorry, multiplying by the reciprocal would mean multiplying by (12) not (1/12) *** sorry about that.

Answer 5

oh ok. thanks

Answer 6

Do you understand how to solve for x now?

Answer 7

yeah, i do. thank youuu. you wanna give me a practice problem so i can prove myself. lol

Answer 8

hmm...pull out another problem from your book and i'll help you work through it :P

Answer 9

okie i got one. x/3 + 3x/4 = 13

Answer 10

i got x=39

Answer 11

hmmm...let me solve it :P did you use the above steps? ^

Answer 12

yes mam

Answer 13

i'm not getting 39.... :\ what did you get as your denominator?

Answer 14

i used 12

Answer 15

and for your numerator?

Answer 16

i left them alone.

Answer 17

here lemme draw out what i did.

Answer 18

lol wait aminute. maybe i did it wrong -_- retrying! :P

Answer 19

oh okay

Answer 20

x/3+ 3x/4 = 13

4x/ 12 + 9x/12 =13

(4x+9x)= (12)(13)

13x = 156

x= ?

Answer 21

oh i didnt know we were suppose to do anything with the numerators. since we didnt in the previous problem

Answer 22

correction: look at the 4rth step :P

Answer 23

OHH. I GET IT NOW. haha my bad. thanks

Answer 24

xD

Answer 25

i recommend you stay online cuz im probably gonna need some more help. :P

Answer 26

and your like my only hope to passing

Answer 27

lol, are the types of problems you're having trouble with like these?

Answer 28

you can always "fan" be by left clicking on my name and "becoming a fan" that way you can message me with your problems! ^_^

Answer 29

me*

Answer 30

Good idea! done. There mostly inequalities, but theres some old geometry stuff that i would like to go over to make sure i can do. Like sine, cosine, tangent. That kinda stuff :P

Answer 31

ohh okay. just post up a new question after closing this one, or send me a message with it xD I'll try my best to help!

Answer 32

okie thanks! your awesomee haha

Answer 33

and if you liked my responses there is a "best response" button to the right :) --->

Answer 34

oh okay! haha. already clicked. wooo

Answer 35

:D