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evaluate cot(arccos5/13)
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sin^2 + cos^2 = 1 1 + cot^2 = csc^2 cot^2 = csc^2 - 1
ok
or simply draw out the triangle and solve for cot = x/y
what does the arccos mean?
|dw:1370273177883:dw|
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arccos relates a ratio to an angle ... its the reverse, or invers, of cosine
for example: cos(45) = 1/sqrt(2) therefore 45 = arccos(1/sqrt(2))
so arccos equals the sin
trig (angle) = ratio angle = arctrig (ratio) if you know the ratio, you can rebuild the triangle no, sin and arccos are not equivalent function
but would it be cot(12/13)
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you are confusing angles and ratios at the moment
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