Question

Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).

y = one thirdx + 7

y = −3x + 3

y = one thirdx + 3

y = −3x + 7

Answer 1

you would have to know that parallel lines have the same slope..

Answer 2

2nd one is right answer.

Answer 3

Equation of a straight line: y = mx + c
Where m is the gradient
2 lines are parallel when the gradient of them both is equal
so as long as you have y = -3x then you can put any number after it
and the new line would be Parallell
e.g.
y = -3x + 56434657567099123
y = -3x + 1

For it to pass through ( -1 , 6 ) then put the numbers in and see what you get ( but dont change the gradient )
e.g.
y = -3x + 3 ( when x = -1 , y = 6 )

Answer 4

thanks so much! i have more do you mind?

Answer 5

nop.

Answer 6

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

y = 2x + 6

y = −one halfx + 3

y = −one halfx + 6

y = 2x + 3

Answer 7

that is the last question

Answer 8

3rd one is answer.y = −one halfx + 6

Answer 9

i cant thank you enough

Answer 10

i amnot sure about last one sorry.

Answer 11

thats okay :) i got it right but i still got a 60 on the overall assignment :( i have to take it again.