y=x^2+32x-120
Y=(x^2+32x+256)-120-256
Y=(x+16)^2-376

Why is the vertex (-16,-376) and not (16,-376)

Question

y=x^2+32x-120
Y=(x^2+32x+256)-120-256
Y=(x+16)^2-376

Why is the vertex (-16,-376) and not (16,-376)

loser66 · Answer

nope, sorry, it's must be  Y= (x+16)^2 -376 
yours lack ^2 and it's not true

anonymous · Answer

ohh. It asked for the vertex (-16,-376)

anonymous · Answer

how is -16 the x in the vertex

noelgreco · Answer

the x-co-ordinate of the vertex of a parabola is $$x = \frac{ -b }{ 2a }$$

anonymous · Answer

attachment

noelgreco · Answer

The vertex form of a quadratic is:

$$y=(x-h)^{2}+k$$

where the coordinates of the vertex are (h,k).

Loser 66 put your quadratic into vertex form 8 days ago.  The minus sign before the h means you have to change the sign to get the proper value of the x-coordinate.