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Find the rate of change of f, df/dt, along the parametric curve x(t)=2t-1, y(t)=3-2t^2 at t=1.
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the rate of change is not the gradient ? partial derivative?
any idea, friends?
dx/dt=2 dy/dt=-4t dx/dt(1)=2 dy/dt(1)=-4
Sorry 66, I know rate of change but have never learned it using parametrics
@Luigi0210 it's ok, it's from cal3
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sure!! you are right.
How do I get the answer, -8 from there?
can you draw out the formula of gradient? to put everything in neat? what is the original question? do they ask you about the direction of rate of change of f ?
the net is not good here, too. I think you are kicked out of the net!!
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