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Mathematics 10 Online
OpenStudy (anonymous):

Find the rate of change of f, df/dt, along the parametric curve x(t)=2t-1, y(t)=3-2t^2 at t=1. 

OpenStudy (loser66):

the rate of change is not the gradient ? partial derivative?

OpenStudy (loser66):

any idea, friends?

OpenStudy (anonymous):

dx/dt=2 dy/dt=-4t dx/dt(1)=2 dy/dt(1)=-4

OpenStudy (luigi0210):

Sorry 66, I know rate of change but have never learned it using parametrics

OpenStudy (loser66):

@Luigi0210 it's ok, it's from cal3

OpenStudy (loser66):

sure!! you are right.

OpenStudy (anonymous):

How do I get the answer, -8 from there?

OpenStudy (loser66):

can you draw out the formula of gradient? to put everything in neat? what is the original question? do they ask you about the direction of rate of change of f ?

OpenStudy (loser66):

the net is not good here, too. I think you are kicked out of the net!!

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