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Mathematics 13 Online
OpenStudy (tiffany_rhodes):

Find the length of the arc of the given curve y^3 = x^2 from (-1,1) to (8,4) @primeralph

OpenStudy (tiffany_rhodes):

I decided to solve for x. So I got x=y^(3/2).

OpenStudy (primeralph):

Yeah, that could work......

OpenStudy (tiffany_rhodes):

and integrated from 1 to 4

OpenStudy (primeralph):

so you're using dx/dy right?

OpenStudy (tiffany_rhodes):

yes.

OpenStudy (primeralph):

answer?

OpenStudy (tiffany_rhodes):

3y^(1/2) / 2?

OpenStudy (tiffany_rhodes):

for the derivative of y^(3/2)

OpenStudy (primeralph):

your final answer.

OpenStudy (tiffany_rhodes):

the integral from 1 to 4 of (1 + 9y/4)^(1/2)

OpenStudy (primeralph):

Do you just need the answer or the whole process?

OpenStudy (tiffany_rhodes):

I get the process. I just wasnt sure if I was computing the antiderivative right because I keep getting the wrong answer.

OpenStudy (primeralph):

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