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Find the length of the arc of the given curve y^3 = x^2 from (-1,1) to (8,4) @primeralph
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I decided to solve for x. So I got x=y^(3/2).
Yeah, that could work......
and integrated from 1 to 4
so you're using dx/dy right?
yes.
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answer?
3y^(1/2) / 2?
for the derivative of y^(3/2)
your final answer.
the integral from 1 to 4 of (1 + 9y/4)^(1/2)
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Do you just need the answer or the whole process?
I get the process. I just wasnt sure if I was computing the antiderivative right because I keep getting the wrong answer.
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