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Find the y-intercept of the function: f(x) = 6˟ + 2
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Plug in x = 0 and evaluate to find the y-intercept
i still dont understand\
f(x) = 6^x + 2 f(0) = 6^0 + 2 f(0) = ??
i got 2 too but my teach has the choices written in pair
teacher
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6^0 = ???
0?
no
any number (but zero) to the zeroth power is always 1
so 6^0 = 1
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oh so is the pair (0,1)
no
6^0 is just part of it
remember the +2 at the end
uggh im sorry this is just kinda confusing
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remember we had 6^0 + 2
replace the 6^0 with 1 since the two are equal
then evaluate
8?
6^0 = 1, so f(x) = 6^x + 2 f(0) = 6^0 + 2 f(0) = 1 + 2 I'm sure you see what to do from here
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f(0)=3
(0,3)
yep
you got it
thank you
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yw
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