How would I write the standard equation for the circle center (-6, 7), r = 9?
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OpenStudy (rajee_sam):
isn't it the same thing we did earlier. They have given you the center and the radius . Put it in the standard form I gave you earlier. You are smart. You should not be posting the same type of question twice.
OpenStudy (anonymous):
Oops, sorry I wrote the wrong thing! My bad.
OpenStudy (anonymous):
I have one quick question @rajee_sam.
What if it was (-6,-8) and it passed through (0,0). What would my radius be?
OpenStudy (rajee_sam):
Your distance between these two points will be the radius. Do you know the distance formula?
OpenStudy (rajee_sam):
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OpenStudy (rajee_sam):
|dw:1370359387911:dw|
OpenStudy (rajee_sam):
@Nvidia64
OpenStudy (anonymous):
=100
OpenStudy (rajee_sam):
100 is r², so r = 10
OpenStudy (anonymous):
So would it be (x+6)^2 + (y+8)^2 = 100? or (x-6)^2 + (y-8)^2 = 10?
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OpenStudy (rajee_sam):
the center is -6,-8
So ( x - (-6) )² + ( y - (-8) )² = 100
which will be
( x+6)² + ( y+8)² = 100