Solve the inequality and type the solution in interval notation. No spaces!
11 ≤ 3x + 5 ≤ 23
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OpenStudy (anonymous):
please help!!!!
OpenStudy (jim766):
this is a compound inequality, really two inequalities
\[11\le3x + 5 \] and \[3x + 5 \le23\]
do you see where I got them?
OpenStudy (anonymous):
you added right
OpenStudy (jim766):
now just solve each
this is a compound inequality, really two inequalities
\[11\le3x + 5 \]
-5 -5
\[6\le3x\]
and \[3x + 5 \le23\]
-5 -5
\[3x \le18\]
OpenStudy (anonymous):
aw my fault you subtracted 5 from both sides
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OpenStudy (jim766):
you can also do it like this
11<= 3x + 5<=23
-5 - 5 -5
6 <= 3x <= 18
-- -- --
3 3 3
2 <= x <= 6
OpenStudy (anonymous):
so then i would combine those 3 for the answer?
OpenStudy (jim766):
I am not sure what they mean by interval notation
but I think the way I wrote it at the end is this
2 <= x <= 6 it means x is greater than = to 2 and less than = to 6
OpenStudy (anonymous):
like this? (2,6)
OpenStudy (jim766):
no, that means just 2 and 6, it also means that one is x and one is y
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