Question

Solve when the equation x^3+6x^2+5x+12 has a root of 4

Answer 1

synthetic division:

Answer 2

NO NEVER USE SYNTHETIC DIVISION!!

Answer 3

\[\sqrt{4x+4-2}\]

Answer 4

why not?

Answer 5

It's the devils work!!!

Answer 6

I have no idea what that mean, sorry. I am glad the help Luigi0210

Answer 7

Calm down Rynal :P

Answer 8

I know that I plug in 4 that will only prove that it's a zero, but other than that i am sorta at a lost.

Answer 9

Do I factor it?

Answer 10

actually, if you plug in 4 you don't get 0

Answer 11

I honestly have no idea what to do for this problem, and i do not know what synthetic division I.

Answer 12

there is something wrong with your equation above

Answer 13

is it x^3+6x^2+5x-12 ?

Answer 14

\[x ^3+6x^2+5x-12\]

Answer 15

that still wouldn't give us 0..

Answer 16

x=1 will satisfies as zero

Answer 17

How would I figure out the roots for this equation in general then?

Answer 18

use synthetic division

Answer 19

you could graph and see where they intersect

Answer 20

the x-axis