Question

help with 3 questions about triangles?

Answer 1

sure?

Answer 2

please help!

Answer 3

you need to remember two things for triangles:
1) cos(a) = (adjacent) / (hypothenuse) (->then sin(a) = (opposite)/(hypothenuse))
2) tan(a) = sin(a)/cos(a)


tan(a) = sin a /cos a = opposite / adjacent = 12/16 right?

Answer 4

i mean tan("x") = 12/16..

Answer 5

yeah 3/4

Answer 6

sure, and the second one is quite immediate too. what do you get?

Answer 7

straightforward*

Answer 8

i just dont know how to do these lol...

Answer 9

sin(x) = opposite / hypothenuse

Answer 10

write the fraction, and simplify

Answer 11

30/34= 15/17?

Answer 12

why 30?

Answer 13

it's the opposite to the angle x, so it's 16/34

Answer 14

and the last one?
how do i figure that one out

Answer 15

now you know x, x = 63°.
They say "use the cosine".
The formula is cos(63) = adj / hyp right?

It turns out that in this equation, only "hyp" is unknown. Therefore you just have to isolate it.

Answer 16

so how do i figure it out?

Answer 17

53*

Answer 18

write the equation for the cosine: \(\cos(53) = \frac{7}{H}\). -> \(H = \dots\). use a calculator to compute cos(53°) and you're done.

Answer 19

my answer is coming out to be .6

Answer 20

for the cos(53) ? yes.
then, what is H?

Answer 21

9.29

Answer 22

what formula did you use?

Answer 23

\[\cos(53°) = \frac7H\\
\iff H = \frac{7}{cos(53°)} = \frac7{0.602} = \dots\]

Answer 24

9.29?

Answer 25

It's not that hard:
if you don't have a calculator, you can use google. it'll tell you "7/0.602 = 11.6279069767 = 11.63" more or less

Answer 26

@ogkat it's done.