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OpenStudy (anonymous):
How would i Simplify 7+i / 2-2i
(Complex Numbers)
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OpenStudy (ivettef365):
You have
7+i 2+2i
----- . -------
2-2i 2+2i
OpenStudy (anonymous):
Then i would now just combine like terms and foil correct?
OpenStudy (ivettef365):
right and remember that i^2 = -1
OpenStudy (anonymous):
ok Thakns!
OpenStudy (ivettef365):
Like when you multiply (2-2i)*(2+2i)
=4-4i^2 = 4-4(-1) = 4+4 = 8
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OpenStudy (anonymous):
ok after i have the step tht you just shown here, do i just keep simplifying it down?
OpenStudy (anonymous):
Speaking with this in mind:
=4-4i^2=4-4(-1)=4+4=8
what is the next step
OpenStudy (ivettef365):
the step I did is the bottom part the top part as follows:
(7+i) *(2+2i)
14+14i+2i+2i^2
14 +16i +2(-1) = 16i + 14-2
16i+12
OpenStudy (ivettef365):
Now you have
16i + 12
--- ----
8 8
OpenStudy (ivettef365):
Now just simplify
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OpenStudy (anonymous):
16i + 12
---- ------
8 8
that wuld be divide each by 8 correct?
OpenStudy (anonymous):
if so , after doing tht i got 8i + 1.5
does not seem correct
OpenStudy (ivettef365):
16/8 = 2, so it would be 2i+3/2
OpenStudy (anonymous):
Thanks for the help :)
OpenStudy (ivettef365):
your welcome :)
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