The slope of the line containing the points (-5, 3) and (-2, 1) is

a.-2/3
b.2/3
c.-3/2

Question

The slope of the line containing the points (-5, 3) and (-2, 1) is


a.-2/3
b.2/3
c.-3/2

anonymous · Answer

$$\frac{ 1-3 }{-2--5} =?$$

anonymous · Answer

Do you get how to figure it out from here?

anonymous · Answer

no :/

jhannybean · Answer

take 

(x1 , y1) = (-5 , 3)
(x2 , y2) = (-2 , 1)

(y2 - y1) /(x2 - x1) = (1 - 3) / (-2 - (-5)) 

simplify

jhannybean · Answer

You have - 2 + 5 , what does that give you?

anonymous · Answer

Okay, so subtract 3 from 1. You get -2. Then, add -2 and 5. The answer is $$-\frac{ 2 }{ 3 }$$

anonymous · Answer

thanks what about this one 

The slope of a line that is perpendicular to a line whose slope is 3/8 is

a.-8/3
b.3/8
c.8/3

jhannybean · Answer

a perpendicular line has a negative and opposite slope

original line slope = m

perpendicular line = - 1/ m 

Can you go from there? :)

anonymous · Answer

no sorry

jhannybean · Answer

m = 3/8 

perpendicular = -1 / (3/8) = -1/3 * 8/1 

simplify this and you'll have your answer.

anonymous · Answer

so the answer is 8/3 right??

jhannybean · Answer

you forgot to multiply by the negative :)

anonymous · Answer

oh so -8/3

anonymous · Answer

Correct :)