Question

HELPPPPP !!!
Add and simplify:

x+1/x + x-3/3x

Answer 1

the expression is

\[\large \frac{x+1}{x} + \frac{x-3}{3x}\]

right?

Answer 2

yeah @jim_thompson5910

Answer 3

\[\large \frac{x+1}{x} + \frac{x-3}{3x}\]


\[\large \frac{3(x+1)}{3x} + \frac{x-3}{3x}\]


\[\large \frac{3x+3}{3x} + \frac{x-3}{3x}\]


\[\large \frac{3x+3+x-3}{3x}\]


\[\large \frac{4x+0}{3x}\]


\[\large \frac{4x}{3x}\]


\[\large \frac{4}{3}\]


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So,

\[\large \frac{x+1}{x} + \frac{x-3}{3x}\]

simplifies to

\[\large \frac{4}{3}\]

In other words,

\[\large \frac{x+1}{x} + \frac{x-3}{3x} = \frac{4}{3}\]

is true for all values of x where \(\large x \neq 0\)

Answer 4

So before you can add the fractions, you need to get all the denominators equal to the LCD (which in this case is 3x)