A concrete cube of side 0.60 m and uniform density 2.0 × 103 kg m–3 is lifted 5.0 m vertically by a
crane.
What is the change in potential energy of the cube?

Question

A concrete cube of side 0.60 m and uniform density 2.0 × 103 kg m–3 is lifted 5.0 m vertically by a
crane.
What is the change in potential energy of the cube?

mos1635 · Answer

formula for potential energy??

anonymous · Answer

i just need an answer if however i require the formula

mos1635 · Answer

????

anonymous · Answer

these are the answers: A 2.2 kJ B 21 kJ C 59 kJ D 450 kJ

anonymous · Answer

its B but i wanna know how to get the answer

mos1635 · Answer

what is the formula for potential energy??

anonymous · Answer

i know that its equal to mgh m for mass, g equals to 9.81 and h for height but i still can solve it; density is related as: mass over volume and well im not sure how to solve it

mos1635 · Answer

|dw:1370515786355:dw|

anonymous · Answer

0.6 X3 as the sides of the cube?

mos1635 · Answer

0.6^3=0.6*0.6*0.6=0.216

anonymous · Answer

ok and next?

mos1635 · Answer

find mass

anonymous · Answer

we have the density so i guess we need the volume and we find the mass

mos1635 · Answer

$$d=\frac{ m }{ V }$$

mos1635 · Answer

but you have allready find volume

anonymous · Answer

oh yes its 0.216

mos1635 · Answer

$$V _{cube}=side ^{3}=a ^{3}=0.6^{3}=0.216$$

anonymous · Answer

ok thanks just found it thanks for your help :)