Question

Find 4 consecutive even integers where the product of the two smaller numbers is 56 less than the product of the two larger numbers. @tcarroll010 @matty546

Answer 1

(2x)(2x + 2) + 56 = (2x + 4)(2x + 6)

4x^2 + 4x + 56 = 4x^2 + 20x + 24

16x = 32

x = 2

So, since your first number is 2x:

4, 6, 8, 10

Answer 2

You have to use 2x, 2x + 2, 2x + 4, and 2x + 6
not x, x + 1, x + 2, x + 3

because you have to force "evenness". That's why you need everything multiplied by "2".

Answer 3

And since this works out to be:

4, 6, 8, and 10

you can verify this by:

(4 x 6) + 56 = (8 x 10)

So, it works.

Answer 4

All good now, @shortie212 ?

Answer 5

yea i am gann posted more @tcarroll010