Question

Two rectangles have the same width. The length of one is 1 foot longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 5 more square feet than the smaller. What is the width of the rectangles? @tcarroll010

Answer 1

For area, we have: A = L x W

The smaller rectangle has: (W)(W + 1)

The larger rectangle has: (W)(W + 2)

The smaller rectangle has 5 less square feet:

(W)(W + 1) + 5 = (W)(W + 2)


Can you solve for "W" now?

Answer 2

no

Answer 3

Start by expanding:

(W)(W + 1)

Answer 4

i dont get it

Answer 5

Hint: (a)(a + b) use distributive property

a^2 + ab

Now, use that as a guide for expanding:

(W)(W + 1)

This is a huge hint you've been given and all you have to do is substitute since you are given all the tools necessary to do this expansion.

Answer 6

is it like this(2)(5+1)

Answer 7

Yes, that is similar.

(2)(5 + 1) = (2)(5) + (2)(1)

Answer 8

i got 12 feet i dont know if i got it correct

Answer 9

Well, (2)(5+1) = 12

But you already substituted W=5, so 5 is the answer, not 12.

Answer 10

(W)(W + 1) + 5 = (W)(W + 2)

W^2 + W + 5 = W^2 + 2W

W = 5

Answer 11

wht is it

Answer 12

All set now?