Mathematics
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OpenStudy (anonymous):
Derivative of x^2+4/3x help
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OpenStudy (abb0t):
\(\large \frac{d}{dx} (a^n) = na^{n-1}\)
OpenStudy (anonymous):
its a fraction
terenzreignz (terenzreignz):
Coefficients don't matter that much :)
@abb0t
\[\large \color{red}* \frac{d}{dx} (a^n) = na^{n-1}\cdot \color{red}{\frac{da}{dx}}\]
terenzreignz (terenzreignz):
Just sayin' @abb0t :D
OpenStudy (anonymous):
I tried doing the quotation rule, but the answer the book gives is different than what I get
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terenzreignz (terenzreignz):
quotient rule?
A better way would be to treat \(\large \frac34 \) just like any constant.
OpenStudy (abb0t):
Sometimes the solution given in a book is simplified to make the solution look "pretty" however, there are also other ways to write a solution.
terenzreignz (terenzreignz):
If you have to get the derivative of
\[\Large ax\]
You wouldn't hesitate to say it's \(\large a\)
(right?)
OpenStudy (anonymous):
\[\frac{ x ^{2}+4 }{ 3x }\]
OpenStudy (anonymous):
thats it
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terenzreignz (terenzreignz):
Well, the case involving
\[\large \frac34x\]
isn't much different
terenzreignz (terenzreignz):
oh okay, that clears things up :D
terenzreignz (terenzreignz):
Quotient rule being
\[\Large \frac{d}{dx}\left[\frac{f(x)}{g(x)}\right]=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}\]
OpenStudy (anonymous):
yes, thats what I used
OpenStudy (anonymous):
but I get a different answer than my book
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terenzreignz (terenzreignz):
Okay, so it all boils down to knowing what f(x), g(x), f'(x), and g'(x) are
terenzreignz (terenzreignz):
What is your answer, by the way?
OpenStudy (anonymous):
I got \[\frac{ 3x ^{2}-12 }{ (3x)^{2} }\]
terenzreignz (terenzreignz):
Okay... and what does the book say?
OpenStudy (anonymous):
the book has this \[\frac{ (x-2)(x+2) }{ (3x)^{2} }\]
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terenzreignz (terenzreignz):
hehe
OpenStudy (anonymous):
???? am I doing something wrong?
terenzreignz (terenzreignz):
okay, wellI'm pretty sure it's like this...
\[\Large \frac{(x-2)(x+2)}{3x^2}\]
terenzreignz (terenzreignz):
no parentheses in the denominator
terenzreignz (terenzreignz):
or am I missing something?
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
no thats what the book has
OpenStudy (anonymous):
so what am I doing wrong
terenzreignz (terenzreignz):
It's different that way. So... just keep calm and take deep breaths...
\[\Large \frac{3x^2-12}{9x^2}\]
Catch me so far?
OpenStudy (anonymous):
yea
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terenzreignz (terenzreignz):
Okay, so why don't we... factor out a 3 in the numerator?
\[\Large \frac{3(x^2-4)}{9x^2}\]
OpenStudy (anonymous):
ok, now i got it
terenzreignz (terenzreignz):
>:)
terenzreignz (terenzreignz):
So, everything all right now?
OpenStudy (anonymous):
i was be stupid. yep.
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terenzreignz (terenzreignz):
Nah, it was the book being nitpicky :D