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What is x2 − 5x − 7 = 0 plugged into the quadratic formula?
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\[\frac{ -b \pm \sqrt{b^2-4(a)(c)} }{ 2a }\]
I think ax2 + bx + c = 0. ?
A B C 1x^2 - 5x -7 = 0
yes if given the form \[ax^2+bx+c=0\] then the quadratic equation is \[x= \frac{ -b \pm \sqrt{b^2-4ac}}{2a}\]
\[\frac{ 5\pm \sqrt{(-5)^2-4(1)(-7)} }{ 2 }\]
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Why thank you my good sir
yw, do you understand where it all came from?
yes I was just having trouble visualizing it
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