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Solve the system: x+y+z=4 x+2y-z=2 3z=x-3y
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matrix time
100% agree
set it up as a matrix
or elimination
@texaschic101 not easy to go on that way
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how would you use elimination for this problem?
you are better set up matrix, texaschic off line. cannot guide you
Not really that hard with elimination. \[x+y+z=4\]\[x+2y-z=2\]\[-x+3y +3z= 0\] Add rows 1 and 2 to get \[2x+3y = 6\] Add rows 2 (mult by 3) and 3 to get \[2x+9y = 6\]Subtract the two resulting rows to get an equation that is very easy to solve :-) Plug result into previous equations.
I prefer elimination....that is just my opinion
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