please help.....I need to solve for x and y
27.98(x/100) + 28.98(0.468) + 29.97(y/100) = 2 I have done it, but I don't know if it is correct. I got : x = 4.75 and y = - 2.3
@jim_thompson5910 ...can you check this please
I had to do quite a bit of rounding
\[27.98\frac{x}{100}+28.98(0.468)+29.97\frac{y}{100}=2\]Multiply through by 100 \[27.98x + 28.98(46.8) + 29.97y=200\]\[27.98x+29.97y=-1156.26\]Plug in your values \[27.98(4.75)+29.97(-2.3) = 132.905 - 68.931\] no cigar...
What were the original equations you had to solve? You've only got 1 equation in 2 unknowns there...
That is the entire problem
This is how I did it ... http://answers.yahoo.com/question/index;_ylt=AhbRn18tPXL8JzIQK3FKflPsy6IX;_ylv=3?qid=20130606164535AAjXXiq
Well, first solve for one of your variables, let's start with y. Solving for y we get y=-0.9336x-38.5807. Plug that back into your equation and you get 0.2798 x+0.2997 (-0.9336x-38.5807)+13.5626 = 2 Just solve for x then you'll be able to solve for y.
Unfortunately you made an arithmetic error on the very first line :-(
(@texaschic101 that is)
28.98*0.468 = 13.5626
I got x=447.37 and y=-456.245
Oh darn.....messed up on the first line...thats bad....makes the entire problem wrong
0.2798x + 0.2997(-0.9336x - 38.5807) + 13.5626 = 2 @whpalmer4 ....can the numbers be rounded to make them shorter ?
because when I distribute the numbers are really long
you can round them at a cost of accuracy in the final result...
so your saying that it is best not to round ?
yes, if you want an answer that makes the problem come out as close as possible... for example, Brenar's numbers (even though they have many digits) give 2.00014 as the answer...
if you just don't like all the writing, why not substitute letters for each different number? ax + b(-cx-d)+e=2 a=0.2798, b=0.2997, etc. then when you've solved for x and y, plug in the numbers
I wouldn't actually do the multiplication until the last possible opportunity...
0.2798x - .27979992x - 11.5405479 + 13.5626 = 2 my calculator is throwing in letters when I try to subtract :/
ax + b (-cx + d) + e = 2 ax -bcx + db + e = 2 ok...I am so lost
there is no unique solution here, you realize?
I really don't know why I am doing this problem...it is not even my problem...it just caught my attention
Your original equation is \[27.98(x/100) + 28.98(0.468) + 29.97(y/100) = 2\]Multiply through by 100: \[27.98x + 28.98(46.8) + 29.97y = 200\]Solve for \(y\)\[29.97y = 200-28.98(46.8)-27.98x\]\[y=\frac{1}{29.97}(200-28.98(46.8)-27.98x)\] Now pick a value of \(x\) and plug it into the formula. Out pops the matching value of \(y\). For any value of \(x\), there's a corresponding value of \(y\). The solution is a straight line...
If you like, you can write it as \(y = -38.5807-0.9336x\)
I like that better
It's just a real-life equation for a line, instead of a sanitized equation like you get in the textbook :-)
Because we have fewer equations than we have unknowns, we don't get a unique solution.
thank you so much @whpalmer4 and @Brenar ......you are great. Did you ever think about being teachers.
Hard to get a teaching job where you get to teach only the interested students :-)
I deleted my answer on yahoo....didn't want to give that person a wrong answer...I should refer him to you...lol
thanks again :) I will close this question now
you're welcome!
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