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OpenStudy (anonymous):
x > 6 or x < -1
-1 < x < 6
x > 6 and x < -1
OpenStudy (anonymous):
You just solved your own problem.
OpenStudy (anonymous):
? lol those are the multiple choice :D @Brenar
OpenStudy (anonymous):
Ah, makes much more sense. First off, since this is an absolute value inequality you'll have to split it into two inequalities as such:
\[-7>2x-5>7\] You have an idea of where to begin?
OpenStudy (anonymous):
B..Probably?
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OpenStudy (anonymous):
Do you understand how I set up the inequality?
OpenStudy (anonymous):
? not really
OpenStudy (zzr0ck3r):
@Brenar this is wrong, a number cant be greater than 7 and less than -7 at the same time...
OpenStudy (anonymous):
x>6 or x<-1
OpenStudy (zzr0ck3r):
This is how we do these
|2x-5|>7
so
2x-5>7
2x-5<-7
solve these
x>6 or x<-1
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OpenStudy (zzr0ck3r):
ie
|a-b|>c <===> a-b>c or a-b<-c
OpenStudy (zzr0ck3r):
−7>2x−5>7
^^^ this makes no sense.
OpenStudy (zzr0ck3r):
that implies, by transitivity, that 7<-7
OpenStudy (zzr0ck3r):
you are thinking of |a-b|<C imples -c<a-b<c I think you are getting this confused with the question in the topic.
OpenStudy (anonymous):
l2x-5l>7
+5 +5
_____________
2x > 12
then divide by 2 and you get
x>6
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OpenStudy (zzr0ck3r):
nope, regular algebra does not work on absolute values.
OpenStudy (zzr0ck3r):
|2x|+5 != |2x+5|
OpenStudy (zzr0ck3r):
or simply plun in -3 to see it is true:)
OpenStudy (anonymous):
yeah but i use that for the second solution
OpenStudy (zzr0ck3r):
we showed both solutions, and what you typed is not correct
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OpenStudy (zzr0ck3r):
l2x-5l>7
+5 +5
^^^is not right
OpenStudy (anonymous):
mathway.com
OpenStudy (zzr0ck3r):
I don't need a website to tell me that |x|+5 is not the same as |x+5|
OpenStudy (zzr0ck3r):
I know its not:)
OpenStudy (zzr0ck3r):
it would be right if you wrote
2x-5>7
+5 +5
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OpenStudy (zzr0ck3r):
but not with the | |
OpenStudy (anonymous):
yes with the absolute value sign
OpenStudy (zzr0ck3r):
ok ....
OpenStudy (zzr0ck3r):
then |x|+5 = |x+5|
OpenStudy (zzr0ck3r):
and so |-3|+5 = 8 = 2 = |-3+5|
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OpenStudy (zzr0ck3r):
so 2=8
OpenStudy (zzr0ck3r):
what is |-3+5|?
what is |-3|+5?
OpenStudy (zzr0ck3r):
you see now?
OpenStudy (anonymous):
and how much math experience do you have?
OpenStudy (zzr0ck3r):
im about to graduate
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OpenStudy (zzr0ck3r):
with honors with a math degree:)
OpenStudy (zzr0ck3r):
you don't have to trust me, show me where you read it and ill show you how you read it wrong.
OpenStudy (anonymous):
take a calculator and repeat the action. also check mathway.com its a calculator.
OpenStudy (anonymous):
middle school?
OpenStudy (zzr0ck3r):
college...
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OpenStudy (anonymous):
proud of you. i just logged on today. doesnt matter to me
OpenStudy (zzr0ck3r):
you asked? maybe grow up....im trying to help because you are telling someone how to do something wrong.
OpenStudy (zzr0ck3r):
answer these questions and you should be able to understand why
what is |-3+5|?
what is |-3|+5?
OpenStudy (anonymous):
hahaha says the person with a name they cant even spell correctly. certaintly not graduating with an english major
OpenStudy (zzr0ck3r):
your name is cristina17?
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OpenStudy (anonymous):
yes captain O
OpenStudy (anonymous):
i know...it is
OpenStudy (anonymous):
try mathway.com
OpenStudy (anonymous):
thats what i said
OpenStudy (zzr0ck3r):
lol omg
what is |-3+5|?
what is |-3|+5?
now
ARE THEY THE SAME???????????????????????
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OpenStudy (anonymous):
haha sorry...
OpenStudy (zzr0ck3r):
think for yourself....don't run to the website:)
OpenStudy (anonymous):
lol mathway.com
OpenStudy (zzr0ck3r):
p.s. solving for x in |x|+5 = |x+5| is not the same thing as saying |x|+5 = |x+5| for all x.....
OpenStudy (zzr0ck3r):
that statement is true if and only if x is 3
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OpenStudy (anonymous):
ok i got it now. use the multiple choice answers and work backwards
l2(7)-5l>7...aka 9>7
l2(-2)-5l>7...aka 9>7
OpenStudy (anonymous):
so the answer x > 6 and x < -1 is correct
OpenStudy (zzr0ck3r):
yes
OpenStudy (anonymous):
that is what i had said earlier...i just lacked the explanation