Which relation does not represent a function? (-8, 4), (-3, 2), (1, 3), (5, -8) (2, 0), (4, 6), (7, 6), (8, 5) (-4, 6), (-1, 1), (0, 4), (4, 7) (1, 2), (2, 5), (5, 7), (1, 3)
The last one, since the domain numbers are not in order of lowest number to highest. D is the answer.!
Look for one where the same x values go to two different y values, this is not a function
Domain does not need to be in order....
But the last is the answer
thanks
Yes it does, the sequence has to be in order from the lowest to highest. A, B, and C are, and D isn't since it goes '1, 2, 5, 1' If the 1 at the end was higher than 5, then it would be a function.
Because 1 goes to 2 and 1 goes to 3
You are very wrong. Sets do not have order. Google it
F(1)=2 and f(1)=3 thus it is not a function
Look at the last line in #1, and the third to last line in #2 here ----> http://www.athometuition.com/functions.php
PS not all functions increase...
The last line says what I said
If x=y then f(x) = f(y)
We have f(1) =2 and f(1)=3
1=1 but f(1) does not equal f(1)
Understand?
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