Question

Solve using the Quadratic Formula
5x^2+7x-2=4x-1

Answer 1

Get it equal to 0 and then plug into the formula.

Answer 2

5x^2+3x-1=0

Answer 3

Now a = 5, b = 3, c = -1 Plug into the formula.

Answer 4

ahh i seee

Answer 5

thank you

Answer 6

yw

Answer 7

@drotzmann The denominator should be 2a

Answer 8

yeah... i meant to write that i didnt realize i for got that sorry haha

Answer 9

First :
We have :
\[5x^2+7x-2=4x-1\iff 5x^2+7x-2-4x+1=0\\\iff 5x^2+3x-1=0\\\]
So :
\[a=5~~ b=3~~c=-1\]
Then
\[\Delta =b^2-4ac=9+4\times5\times 1=54>0\]
There exists 2 solutions :
\[x_1=\frac{-b+\sqrt\Delta}{2a}=\frac{-3+\sqrt{54}}{10}\\x_2=\frac{-b+\sqrt\Delta}{2a}=\frac{-3-\sqrt{54}}{10}\]

Answer 10

\[ax ^{2}+bx+c=0\]
\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

there i fixed it

Answer 11

\[\frac{ -3\pm \sqrt{29} }{ 6 }\]
the answer
or you can simplify it even more

Answer 12

(-2.102, -3.897) these should be the two answers