graphing cosine functions help! http://puu.sh/3byUE.png
I know that the period is 2 and the amplitude is 2. And i know that the cosine function is going to start with y = 2cos but I'm not sure how to finish it. And I also have no idea how to do part b.
@dan815
and are you sure? the graph seems a bit condensed
i thought so. i know that the amplitude is the first number in a cosine function y = a cos b x, where a = amplitude
Well the amp is right for sure
if the amplitude is correct, then the period is correct too, right?
The period is determined by the number in front of the x right?
if i use 2 cos 2x and check it with another graph it doesn't look right though :(
That's cause the equation is actually 2cos4x
can you tell me how you found that?
It was more of a trial and error thing, first I tried 2cos .5x, which turned out to be a bit big, so i did 2cos2x, and finally 2cos4x
awesome. thank you so much.
and btw the period is pi/2
Do you need help with part b or do you got that?
if you can help me that'd be great. i've never solved a question like it before.
the question is basically asking, where does the graph have it's lowest and highest points between 2pi. And where it crosses the x-axis
THe period is pi/2
lowest point is -2, highest point is 2, and crosses the x axis between 3/8pi, right?
That has already been mentioned, but thank you professor
Crosses the X axis every pi/4 starting at pi/8
He can walk you through part b Megan, good luck!
No he can xD I'm going back to Pawn Stars!
thanks @Luigi0210! @FutureMathProfessor so how would i represent that in the inequality?
haha have fun :)
aw come on, I don't really know how to explain it.. @FutureMathProfessor
Max: pi/2, pi, 3pi/2, 2pi Min: pi/4, 3pi/4, 5pi/4, 7pi,4 Zero: pi/8, 3pi/8, 5pi/8, 7pi/8, 9pi/8, 11pi/8, 13pi/8, 15pi/8
and I didn't give you a mesal for nothing
*medal
Me neither
Thank you
But yea, that's your answer megan ^_^'
thanks a lot guys!
Medal me
too late, I got it :D
Take his medal away and medal me instead :D
aw, that would make me upset -_-
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