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\[\lim_{n \rightarrow \infty} \frac{5(3^n+1)-4(7^n+1)}{2\times 3^n+9 \times 7^n}\]
have u tried it yet?
yes..
well id probably say divide num and denum by \(7^n\)\[\lim_{n \rightarrow \infty} \frac{5(3^n+1)-4(7^n+1)}{2\times 3^n+9 \times 7^n}=\lim_{n \rightarrow \infty} \frac{5((\frac{3}{7})^n+(\frac{1}{7})^n)-4(1+(\frac{1}{7})^n)}{2\times (\frac{3}{7})^n+9}\]use the fact that \((|a|<1)^n \) will be zero as n approaches to infty
oh yes..now, i got -4/9
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@mukushla thank u so much
very welcome :)
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