What is the electric charge of a ring-shaped metallic washer ?
Equation of a density of a ring \[\rho(x,y)=(x^2+y^2)^{3/2}\]
Sorry , Real={(x,y)in Real^2 | 1le x^2+y^2 le 2}
x^2+y^2-xy=\frac{x^2}{2}+\frac{y^2}{2}+\frac{(x-y)^2}{2} I Think This What You Have To Do Its Been A While So You Might Want To Double Check
Did You try Working it Out ?
Not sure, but I came up with this
So the charge is π C
i dont have this course till my next year, but whats the formula u are trying to implement? u want to take the integral of the density at all volume element?
Hey ! Yes since the electric charge can be determined by density and volume it occupies, I decided to implement mass integration but for charge. Something still feels not quite right
Ohh Hold On I Think there is something Missing in that case i was using a different Way to solve it /:
yes thats what i was going to suggest the mass formula for this
but what is that other found on your function?
1<x^2+y^2<?
bound*
|dw:1370784948370:dw|
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