If two numbers have arithmetic mean 2700 and harmonic mean 75, find their geometric mean.
does that seem correct @vinhu ?
Not quite ! Since the answer is less than 999
might call in the big guns, hang on @Jhannybean and @oldrin.bataku can you guys help...?
let the two numbers be a,b.. arithmetic mean=a+b/2.. geometric mean=sqrt(ab).. two equations, two variables.. find a and b first..
once you have the two numbers.. (1/a + 1/b)/2 gives you the harmonic mean...
ah, cheers @yrelhan4
:)
and.. i should also mention it here, arith mean*geom mean is not equal to harmonic mean.. but for n=2. harmonic mean=G^2/A
we have n=2 here, so doesnt that mean that sqrt (harmonic x Arith) = geometric...?
geometric^2 on the rhs.
sqrt on the LHS...
ah, missed it. my bad. yes thats right.
so my initial guess was correct, and we dont have to solve for a and b...?
no you dont, if you know this formula. but again, the best and the safest thing is to start from the basics.. these formulas are certainly not for beginners.. and i thought you wrote, arith mean*geom=harmonic mean or something like that. sorry about that.
and i hope @vinhu got it?
O_o
no, good point, how you get it is important but with this: "once you have the two numbers.. (1/a + 1/b)/2 gives you the harmonic mean..." i think harmonic is n/(1/a + 1/b), so it should be 2 / (1/a + 1/b)... yeah?
err wth. i am really messing it up today. yes. 1/H=(1/a + 1/b)/2.. so H=2/(1/a + 1/b).
cool, thanks man, i learnt something new just then, cheers @yrelhan4
I was wrong twice. thanks to you too. :)
Could anyone summarize the point for me since I haven't learned this kind of mathematics before !
ok look.. arithmetic mean for two numbers= a+b/2 geometric mean= sqrt(ab) harminic mean= 2/(1/a+1/b).. you are given the values of arith and geom mean.. solve those two equations and find the values of a and b.. then put those values in the third equation to get your answer.
I'm still in the middle of nowhere. More detail please!!! My a , b is extremely huge. Also they are decimal numbers !
Just round them off to up to one decimal points.. and you have all the details you need to solve this.
a= 37.7 ish, b = 5362.2 ish... yeah? @vinhu
all u need so do is solve them like a series of simultaneous equations arithmetic mean for two numbers= a+b/2 2700 = a + b / 2 5400 = a + b so a = 5400 - b plug that into: harmonic mean= 2/(1/a+1/b) 75 = 2/(1/a+1/b) and a = 5400 - b so 75 = 2/(1/(5400 - b)+1/b) solve for b use that to find a use a and b to find geometirc mean ( sqrt (axb))
just an alternate way....might be easier. 5400 = a+b 75= 2ab/ (a+b) = 2ab/ 5400 so, ab = 75*5400/2 = 202500 and Geometric mean is just \(\sqrt{ab}=\sqrt{202500}=450\) see, not much solving was involved :)
and definitely no need to find a and b.
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