Question

What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3

Answer 1

the equation of a line is:y-y1=m(x-x1) where m is the slope.
y-(-2))=1(x-1)/3
y+2=(x-1)/3
3(y+2)=x-1
3y+6=x-1
3y+5=x
x-3y=5
which is the equation of the line.

Answer 2

We can write :
\[y=\frac13x+b\]
To find b we substitute with the point (1,-2) like this :
\[-2=\frac13\times 1 +b\]
So :
\[b=-2-\frac13=-\frac73\]
Therefore :
\[y=\frac13x-\frac73\]

Answer 3

oh i did a mistake actually it will be
3y+6=x-1
3y+7=x
so x-3y=7 is the equation..