A 30.0 μF capacitor is initially charged with 15.0 mC. It is then discharged through a 200.0 Ω resistor. What is the maximum current during the discharge?

Question

anonymous · Answer

@amistre64

amistre64 · Answer

i havent delved into electrical stuff to know if im working it right or not.  id have to google for an idea to run with

amistre64 · Answer

something like this http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capdis.html

amistre64 · Answer

i = Q'

Q = C Vb e^(-t/(RC))

Q' = -Vb/R e^(-t/(RC)) 

i beleive R is resistance, Vb is initial voltage charge, and C might be the capacitor info

anonymous · Answer

$$I _{0}=\frac{ Q _{0} }{ C*R }=2.5A$$

anonymous · Answer

i found answer thx