Question

d/dx(integral from 3 to e^x of sin(t^2-3t)dt - please help with part of this problem.

Answer 1

can you help me with a question?

Answer 2

so I replaced all of the t terms with e^x and got.\[\int\limits_{0}^{e^x}\sin((e^x)^2-3e^x)\]

Answer 3

so now I need to multiply the derivative using chain rule.. right? do I take the derivative of everything that is in the parens.. or just the upper limit of integration? or.. the solution says e^x sin(e^(2x)-3e^x) and I just dont understand which derivative to take to get that e^x out front.