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What are the x-intercept(s) of the graph of y − 8 = x2 − 6x?
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a. (−2, 0) and (4, 0) b. (2, 0) and (−4, 0) c. (2, 0) and (4, 0) d. (−2, 0) and (−4, 0)
It's B right?
just substitute the y for 0, then you have when y=0 0 - 8 = x^2 -6x
then you have 0 = x^2 -6x + 8, do you know how to solve this
and b is not right
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I don't know how to solve it
0 = (x-2)(x-4) (when you multiply this you will get same equation x^2-6x+8) therefore you have x-2 = 0 and x - 4 = 0 x=2 and x=4, so the values would be (2,0) and (4,0)
Thanks!
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