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Algebra
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Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.
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i dont get this .
start with anything times \(x+2\) then subtract 4
here is my example \[(x+5)(x+2)-4\] you can make up your own
so (x+3)(x+2)-4 do i have to solve it ?
you mean "multiply" probably
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ok so (x^2+5x+6)
i think you forgot to subtract 4
how do i do that ?
how do you subtract 4 ?
\[x^2+5x+6-4=?\]
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ohh ok . umm im confused .
what is \(6-4\) ?
2
ok so what is \[x^2+5x+6-4\]?
x^2 + 5x+2
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yup
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